The volume of 1 g of methane (CH_4),ethane ( | vedclass

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(A) Using the ideal gas equation: $PV = nRT = \frac{w}{M_w} RT$Rearranging for volume: $V = \frac{wRT}{P M_w}$Given values: $w = 1 \ g$,$R = 0.0821 \

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$495$

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(A) Using the ideal gas equation: $PV = nRT = \frac{w}{M_w} RT$Rearranging for volume: $V = \frac{wRT}{P M_w}$Given values: $w = 1 \ g$,$R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$,$T = 350 \ K$,$P = 1 \ atm$,and molar mass of butane $(C_4H_{10}) = 4 	imes 12 + 10 	imes 1 = 58 \ g/mol$.Substituting the values: $V = \frac{1 	imes 0.0821 	imes 350}{1 	imes 58} \approx 0.495 \ L$Since $1 \ L = 1000 \ cm^3$,$V = 0.495 	imes 1000 = 495 \ cm^3$.

The volume of $1 \ g$ of methane $(CH_4)$,ethane $(C_2H_6)$,propane $(C_3H_8)$,and butane $(C_4H_{10})$ is measured at $350 \ K$ and $1 \ atm$ pressure. What will be the volume of butane in $cm^3$?

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