For an ideal gas,the volume-temperature graph | vedclass

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Question

(A) According to the ideal gas equation,$PV = nRT$,so $V = (nR/P)T$. This represents a straight line equation $y = mx$,where the slope $m = nR/P$. Sin

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$P_1 > P_3 > P_2$

Vedclass · Answer

(A) According to the ideal gas equation,$PV = nRT$,so $V = (nR/P)T$. This represents a straight line equation $y = mx$,where the slope $m = nR/P$. Since the slope is inversely proportional to pressure $(m \propto 1/P)$,the line with the smallest slope corresponds to the highest pressure. Looking at the graph,the slope of the line for $P_1$ is the smallest,followed by $P_3$,and then $P_2$ (which has the largest slope). Therefore,the correct order of pressure is $P_1 > P_3 > P_2$.

For an ideal gas,the volume-temperature graph at constant mass is shown below. What is the correct order of pressure?

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