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(A) The average velocity $(v_{avg})$ of gas molecules is given by the formula: $v_{avg} = \sqrt{\frac{8RT}{\pi M}}$.This implies that $v_{avg} \propto

Vedclass · Accepted Answer

$0.6$

Vedclass · Answer

(A) The average velocity $(v_{avg})$ of gas molecules is given by the formula: $v_{avg} = \sqrt{\frac{8RT}{\pi M}}$.This implies that $v_{avg} \propto \sqrt{T}$.Given $T_1 = 27 + 273 = 300\,K$ and $v_1 = 0.3\,m/s$.Given $T_2 = 927 + 273 = 1200\,K$.Using the ratio: $\frac{v_2}{v_1} = \sqrt{\frac{T_2}{T_1}}$.$\frac{v_2}{0.3} = \sqrt{\frac{1200}{300}} = \sqrt{4} = 2$.$v_2 = 0.3 	imes 2 = 0.6\,m/s$.

The average velocity of ideal gas molecules at $27\,^oC$ is $0.3\,m/s$. The average velocity at $927\,^oC$ is .......... $m/s$.

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