In a face-centered cubic $(FCC)$ unit cell,how many unit cells share an atom located at the face center?

$A$ compound is formed by elements $A$ and $B$. This crystallizes in a cubic structure where atoms $A$ are at the corners of the cube and atoms $B$ are at the body center. The simplest formula of the compound is:

An element crystallises in a face-centred cubic (fcc) unit cell with cell edge $a$. The distance between the centres of two nearest octahedral voids in the crystal lattice is

$CsBr$ has a $bcc$ structure. If the edge length is $4.3 \ \overset{\circ}{A}$,what is the minimum distance between $Cs^+$ and $Br^-$ ions in $\overset{\circ}{A}$?

What is the number of atoms per unit cell in a face-centered cubic $(FCC)$ crystal lattice?

What is the total number of ions present in one unit cell of sodium chloride lattice?