In the equation $PV = nRT$,the number of moles per liter can be expressed as:

Two separate bulbs contain ideal gases $A$ and $B$. The density of gas $A$ is twice that of gas $B$. The molecular mass of $A$ is half that of gas $B$. The two gases are at the same temperature. The ratio of the pressure of $A$ to that of gas $B$ is

$A$ gas occupies $0.418 \, L$ at $27 \, ^oC$ and $740 \, mm \, Hg$ pressure. If the mass of the gas is $3.0 \, g$,what is its molar mass?

$34.05 \ mL$ of phosphorus vapor weighs $0.0625 \ g$ at $546 \ ^oC$ and $0.1 \ bar$ pressure. What is the molar mass of phosphorus (in $g/mol$)?

The mathematical form of Charles's law is given by $V_{t} = V_{0} \left( \frac{273.15 + t}{273.15} \right)$. Using this equation,explain the relationship between volume $(V)$ and temperature $(T)$ in Kelvin.

At $25 \, ^\circ C$ temperature and $760 \, mm \, Hg$ pressure,the volume of a gas is $600 \, mL$. Calculate the pressure when the volume of this gas becomes $640 \, mL$ at $10 \, ^\circ C$ temperature. Use the ideal gas equation: $\frac{p_1 V_1}{T_1} = \frac{p_2 V_2}{T_2}$