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(A) Volume of unit cell $(V) = 24 	imes 10^{-24} \, cm^3$. Density of element $(ho) = 7.2 \, g \, cm^{-3}$. Total mass of element $= 200 \, g$. Num

Vedclass · Accepted Answer

$3.472 	imes 10^{24} \, 	ext{atoms}$

Vedclass · Answer

(A) Volume of unit cell $(V) = 24 	imes 10^{-24} \, cm^3$. Density of element $(ho) = 7.2 \, g \, cm^{-3}$. Total mass of element $= 200 \, g$. Number of atoms per unit cell $(n) = (8 	ext{ corners} 	imes 1/8) + 2 	ext{ body diagonal atoms} = 1 + 2 = 3 	ext{ atoms}$. Total number of unit cells $= \frac{	ext{Total Mass}}{	ext{Mass of one unit cell}} = \frac{	ext{Total Mass}}{	ext{Volume} 	imes 	ext{Density}} = \frac{200}{24 	imes 10^{-24} 	imes 7.2} = 1.1574 	imes 10^{24} 	ext{ unit cells}$. Total number of atoms $= n 	imes 	ext{Total number of unit cells} = 3 	imes 1.1574 	imes 10^{24} = 3.472 	imes 10^{24} 	ext{ atoms}$.

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