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Question

(A) The wavelength $\lambda$ is calculated using the formula $\lambda = \frac{c}{
u}$,where $c = 3 	imes 10^8 \, m \, s^{-1}$.For the first station:

Vedclass · Accepted Answer

$267.86 \, m, \, 3.0395 \, m$

Vedclass · Answer

(A) The wavelength $\lambda$ is calculated using the formula $\lambda = \frac{c}{
u}$,where $c = 3 	imes 10^8 \, m \, s^{-1}$.For the first station: $
u_1 = 1120 \, kHz = 1120 	imes 10^3 \, s^{-1}$.$\lambda_1 = \frac{3 	imes 10^8 \, m \, s^{-1}}{1120 	imes 10^3 \, s^{-1}} = 267.86 \, m$.For the second station: $
u_2 = 98.7 \, MHz = 98.7 	imes 10^6 \, s^{-1}$.$\lambda_2 = \frac{3 	imes 10^8 \, m \, s^{-1}}{98.7 	imes 10^6 \, s^{-1}} = 3.0395 \, m$.

$A$ particular radio station broadcasts at a frequency of $1120 \, kHz$. Another radio station broadcasts at a frequency of $98.7 \, MHz$. What will be the wavelength of the radiation for each station?

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