(B) The orbital angular momentum of an electron is given by the formula: $L = \sqrt{l(l+1)} \frac{h}{2\pi}$.For an $s$-orbital,the azimuthal quantum n

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(B) The orbital angular momentum of an electron is given by the formula: $L = \sqrt{l(l+1)} \frac{h}{2\pi}$.For an $s$-orbital,the azimuthal quantum number $(l)$ is $0$.Substituting $l = 0$ into the formula: $L = \sqrt{0(0+1)} \frac{h}{2\pi} = 0$.Therefore,the orbital angular momentum of an electron in a $2s$-orbital is $0$.