Calculate the wavenumber bar{v} in cm^{-1} fo | vedclass

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Question

(C) The wavenumber $\bar{v}$ is defined as the reciprocal of wavelength $\lambda$.$\bar{v} = \frac{1}{\lambda} = \frac{1}{5800 \ \mathring{A}} = \frac

Vedclass · Accepted Answer

$5.1 	imes 10^{14} \ s^{-1}$

Vedclass · Answer

(C) The wavenumber $\bar{v}$ is defined as the reciprocal of wavelength $\lambda$.$\bar{v} = \frac{1}{\lambda} = \frac{1}{5800 \ \mathring{A}} = \frac{1}{5800 	imes 10^{-8} \ cm} = 1.724 	imes 10^{4} \ cm^{-1}$.To find the frequency $
u$,we use the relation $
u = c 	imes \bar{v}$,where $c = 3 	imes 10^{10} \ cm \ s^{-1}$.$
u = (3 	imes 10^{10} \ cm \ s^{-1}) 	imes (1.724 	imes 10^{4} \ cm^{-1}) = 5.17 	imes 10^{14} \ s^{-1}$.Rounding to the nearest option,the frequency is $5.1 	imes 10^{14} \ s^{-1}$.

Metal	$Li, Na, K, Mg, Cu, Ag, Fe, Pt, W$
$\phi \ (eV)$	$2.4, 2.3, 2.2, 3.7, 4.8, 4.3, 4.7, 6.3, 4.75$

Calculate the wavenumber $\bar{v}$ in $cm^{-1}$ for yellow radiation having a wavelength of $5800 \ \mathring{A}$.

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