The atomic number of the element (in ground state) having the maximum number of unpaired $3p$ electrons is:

Correct set of four quantum numbers for the outermost electron of rubidium $(Z=37)$ is :

Which one of the following sets of quantum numbers is not possible for a $4p$ electron?

Which of the following orbitals has the same value of $(n+l)$ as that of the $3d$ orbital?

The number of correct statements from the following:
$A.$ For $1s$ orbital,the probability density is maximum at the nucleus.
$B.$ For $2s$ orbital,the probability density first increases to maximum and then decreases sharply to zero.
$C.$ Boundary surface diagrams of the orbitals enclose a region of $100\%$ probability of finding the electron.
$D.$ $p$ and $d$-orbitals have $1$ and $2$ angular nodes respectively.
$E.$ Probability density of $p$-orbital is zero at the nucleus.

The number of orbitals associated with quantum numbers $n=5, m_s=+\frac{1}{2}$ is