What is the total spin for the electronic con | vedclass

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(A) The atomic number of fluorine $(F)$ is $9$. The electronic configuration of fluorine is $1s^2 2s^2 2p^5$. In the $2p$ subshell,there are $5$ elect

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$0.5$

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(A) The atomic number of fluorine $(F)$ is $9$. The electronic configuration of fluorine is $1s^2 2s^2 2p^5$. In the $2p$ subshell,there are $5$ electrons. According to Hund's rule,the electrons are filled as: $2p_x^2, 2p_y^2, 2p_z^1$. The paired electrons have spins of $+1/2$ and $-1/2$,which cancel each other out. There is only one unpaired electron in the $2p_z$ orbital. The total spin $(S)$ is equal to $n 	imes (1/2)$,where $n$ is the number of unpaired electrons. Here,$n = 1$,so $S = 1 	imes (1/2) = 0.5$.

What is the total spin for the electronic configuration of fluorine $(F)$?

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