For a Bohr atom,the angular momentum of an el | vedclass

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(D) According to $Bohr's$ postulate,the angular momentum $(L)$ of an electron in a stationary orbit is quantized and is an integral multiple of $\frac

Vedclass · Accepted Answer

$\frac{n h}{2 \pi}$

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(D) According to $Bohr's$ postulate,the angular momentum $(L)$ of an electron in a stationary orbit is quantized and is an integral multiple of $\frac{h}{2 \pi}$.Mathematically,this is expressed as: $L = mvr = \frac{n h}{2 \pi}$,where $n = 1, 2, 3, .....$ is the principal quantum number,$h$ is $Planck's$ constant,and $m$ is the mass of the electron.

For a $Bohr$ atom,the angular momentum of an electron is given by $M(n = 1, 2, 3, .....)$ :

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