What should be the ratio of velocities of CH_ | vedclass

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(C) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.For methane $(CH_4)$,$\lambda_{CH_4} = \frac{h}{m_{CH_4} 	imes v_{CH_4}}$.For oxyge

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$2 : 1$

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(C) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.For methane $(CH_4)$,$\lambda_{CH_4} = \frac{h}{m_{CH_4} 	imes v_{CH_4}}$.For oxygen $(O_2)$,$\lambda_{O_2} = \frac{h}{m_{O_2} 	imes v_{O_2}}$.Since the wavelengths are equal,$\lambda_{CH_4} = \lambda_{O_2}$.Therefore,$m_{CH_4} 	imes v_{CH_4} = m_{O_2} 	imes v_{O_2}$.$\frac{v_{CH_4}}{v_{O_2}} = \frac{m_{O_2}}{m_{CH_4}} = \frac{32}{16} = 2$.Thus,the ratio of velocities is $2 : 1$.

What should be the ratio of velocities of $CH_4$ and $O_2$ molecules so that they are associated with de Broglie waves of equal wavelength?

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