The number of valence electrons in Fe^{2+} io | vedclass

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Question

(A) The atomic number of $Fe$ is $26$. The electronic configuration of neutral $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms an $Fe^{2+}$ ion,it loses two

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) The atomic number of $Fe$ is $26$. The electronic configuration of neutral $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms an $Fe^{2+}$ ion,it loses two electrons from the outermost $4s$ orbital.Thus,the electronic configuration of $Fe^{2+}$ becomes $[Ar] 3d^6$.The valence electrons are the electrons in the outermost shell or the partially filled $d$-subshell involved in bonding. For $Fe^{2+}$,the $3d$ electrons are considered valence electrons. There are $6$ electrons in the $3d$ subshell.

List-$I$ (Element)	List-$II$ (Block)
$(A)$ $Ra$	$(I)$ $p$-block
$(B)$ $Uuq$	$(II)$ $s$-block
$(C)$ $Ds$	$(III)$ $f$-block
$(D)$ $Fm$	$(IV)$ $d$-block

List-$I$ (Elements)	List-$II$ (Group)
$A$. $Mn, Tc, Re$	$IV$. $7$
$B$. $Zn, Cd, Hg$	$I$. $12$
$C$. $Ti, Zr, Hf$	$II$. $4$
$D$. $Ga, In, Tl$	$V$. $13$

The number of valence electrons in $Fe^{2+}$ ion $(Fe = 26)$ is .......

Similar Questions

Which elements of the $3d$ series do not show variable valency?

Identify the incorrect statement among the following.

Which among the following elements does not have any electron in the $f-$subshell in either its expected or observed electronic configuration?

Match the following:
List-$I$ (Element) List-$II$ (Block)
$(A)$ $Ra$ $(I)$ $p$-block
$(B)$ $Uuq$ $(II)$ $s$-block
$(C)$ $Ds$ $(III)$ $f$-block
$(D)$ $Fm$ $(IV)$ $d$-block

The correct answer is

Match the following elements in List-$I$ with their respective groups in List-$II$.
List-$I$ (Elements) List-$II$ (Group)
$A$. $Mn, Tc, Re$ $IV$. $7$
$B$. $Zn, Cd, Hg$ $I$. $12$
$C$. $Ti, Zr, Hf$ $II$. $4$
$D$. $Ga, In, Tl$ $V$. $13$

The correct answer is:

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