(B) The de Broglie wavelength is given by $\lambda = \frac{h}{mv}$.For particle $X$: $\lambda_X = \frac{h}{m_X v_X} = 1 \ \mathring{A}$.For particle $

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(B) The de Broglie wavelength is given by $\lambda = \frac{h}{mv}$.For particle $X$: $\lambda_X = \frac{h}{m_X v_X} = 1 \ \mathring{A}$.For particle $Y$: $m_Y = 0.25 m_X$ and $v_Y = 0.75 v_X$.Therefore,$\lambda_Y = \frac{h}{m_Y v_Y} = \frac{h}{(0.25 m_X)(0.75 v_X)} = \frac{h}{0.1875 m_X v_X}$.Substituting $\lambda_X = \frac{h}{m_X v_X} = 1$,we get $\lambda_Y = \frac{1}{0.1875} = \frac{1}{3/16} = \frac{16}{3} \approx 5.33 \ \mathring{A}$.

Class 11 Chemistry Structure of Atom De Broglie's principle

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The de Broglie wavelength of a particle $X$ moving with a certain velocity is $1 \ \mathring{A}$. If the mass of $Y$ is $25\%$ of $X$ and its velocity is $75\%$ of $X$,then the de Broglie wavelength of $Y$ will be ........... $\mathring{A}$.

A
$3$
B
$5.33$
C
$6.88$
D
$48$

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Class 11

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Structure of Atom

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De Broglie's principle

If the wavelength is $5894 \, \mathring{A}$,the velocity of light is $3 \times 10^8 \, m/s$,and the value of $h$ is $6.6252 \times 10^{-34} \, kg \cdot m^2/s$,what will be the mass of a sodium photon?

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If $a_0$ is denoted as the Bohr radius of the hydrogen atom,then what is the de-Broglie wavelength $(\lambda)$ of the electron present in the $n^{th}$ orbit of the hydrogen atom?

MediumJEE MAIN 2025

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The de Broglie wavelength $(\lambda)$ associated with a photoelectron varies with the frequency $(v)$ of the incident radiation as,[$v_0$ is threshold frequency]:

DifficultJEE MAIN 2019

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The wavelength (in $m$) of a particle of mass $1.67 \times 10^{-27} \ kg$ moving with velocity of $3.97 \times 10^6 \ m \ s^{-1}$ is:

MediumAP EAMCET 2017

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The de Broglie wavelength of a tennis ball of $60 \ g$ moving with a velocity of $10 \ m/s$ is approximately

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The de Broglie wavelength of a particle $X$ moving with a certain velocity is $1 \ \mathring{A}$. If the mass of $Y$ is $25\%$ of $X$ and its velocity is $75\%$ of $X$,then the de Broglie wavelength of $Y$ will be ........... $\mathring{A}$.

Similar Questions

If the wavelength is $5894 \, \mathring{A}$,the velocity of light is $3 \times 10^8 \, m/s$,and the value of $h$ is $6.6252 \times 10^{-34} \, kg \cdot m^2/s$,what will be the mass of a sodium photon?

If $a_0$ is denoted as the Bohr radius of the hydrogen atom,then what is the de-Broglie wavelength $(\lambda)$ of the electron present in the $n^{th}$ orbit of the hydrogen atom?

The de Broglie wavelength $(\lambda)$ associated with a photoelectron varies with the frequency $(v)$ of the incident radiation as,[$v_0$ is threshold frequency]:

The wavelength (in $m$) of a particle of mass $1.67 \times 10^{-27} \ kg$ moving with velocity of $3.97 \times 10^6 \ m \ s^{-1}$ is:

The de Broglie wavelength of a tennis ball of $60 \ g$ moving with a velocity of $10 \ m/s$ is approximately

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