How many electrons are present in an atom wit | vedclass

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(B) The electronic configuration of an element with atomic number $Z = 104$ (Rutherfordium) is $[Rn] \ 5f^{14} \ 6d^2 \ 7s^2$.We need to identify orbi

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(B) The electronic configuration of an element with atomic number $Z = 104$ (Rutherfordium) is $[Rn] \ 5f^{14} \ 6d^2 \ 7s^2$.We need to identify orbitals where $(n + l) = 8$:For $5f$: $n = 5, l = 3 \implies n + l = 5 + 3 = 8$.For $6d$: $n = 6, l = 2 \implies n + l = 6 + 2 = 8$.For $7p$: $n = 7, l = 1 \implies n + l = 7 + 1 = 8$.For $8s$: $n = 8, l = 0 \implies n + l = 8 + 0 = 8$.In the configuration $[Rn] \ 5f^{14} \ 6d^2 \ 7s^2$:- The $5f$ orbital has $14$ electrons.- The $6d$ orbital has $2$ electrons.- The $7p$ and $8s$ orbitals are empty.Total electrons with $(n + l) = 8$ are $14 + 2 = 16$.

How many electrons are present in an atom with atomic number $Z = 104$ for which $(n + l) = 8$?

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