For the reaction 4A + B rightarrow 2C + 2D,wh | vedclass

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(B) For the reaction $4A + B \rightarrow 2C + 2D$,the rate of reaction is given by: $-\frac{1}{4} \frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{1}{2} \fr

Vedclass · Accepted Answer

The rate of appearance of $C$ is half the rate of disappearance of $B$.

Vedclass · Answer

(B) For the reaction $4A + B ightarrow 2C + 2D$,the rate of reaction is given by: $-\frac{1}{4} \frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{1}{2} \frac{d[C]}{dt} = \frac{1}{2} \frac{d[D]}{dt}$. From this,we can derive: $1$. Rate of disappearance of $B$ $(-\frac{d[B]}{dt})$ is $1/4$ of the rate of disappearance of $A$ $(-\frac{d[A]}{dt})$. This is correct. $2$. Rate of appearance of $C$ $(\frac{d[C]}{dt})$ is $2 	imes (-\frac{d[B]}{dt})$. The statement says it is half,which is incorrect. $3$. Rate of formation of $D$ $(\frac{d[D]}{dt})$ is $\frac{1}{2} 	imes (-\frac{d[A]}{dt})$. This is correct. $4$. Rate of formation of $C$ and $D$ are equal $(\frac{d[C]}{dt} = \frac{d[D]}{dt})$. This is correct. Therefore,the incorrect statement is $B$.

For the reaction $4A + B \rightarrow 2C + 2D$,which of the following statements is incorrect?

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