For the reaction $RCl + NaOH_{(aq)} \rightarrow ROH + NaCl$,the rate is given by $Rate = K_1[RCl]$. What will happen to the reaction rate?
- AIt will double if the concentration of $NaOH$ is doubled.
- BIt will be halved if the concentration of $RCl$ is halved.
- CIt decreases with an increase in the temperature of the reaction.
- DIt remains unaffected by an increase in the temperature of the reaction.
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Similar Questions
What is the order of the following reaction: $2 H_2 O_{2(g)} \longrightarrow 2 H_2 O_{(l)} + O_{2(g)}$?
For the reaction $2 A + B \longrightarrow D + E$,the following mechanism has been proposed: $A + B \longrightarrow C + D$ (slow) and $A + C \longrightarrow E$ (fast). Determine the rate law.
The following are the rate constants of two different reactions. What is the overall order of each reaction?
$(a)$ $2.1 \times 10^{-2} \ mol \ L^{-1} \ s^{-1}$
$(b)$ $4.5 \times 10^{-3} \ min^{-1}$
$(a)$ $2.1 \times 10^{-2} \ mol \ L^{-1} \ s^{-1}$
$(b)$ $4.5 \times 10^{-3} \ min^{-1}$
Medium
View SolutionThe following mechanism has been proposed for the reaction of $NO$ with $Br_2$ to form $NOBr$:
$NO_{(g)} + Br_{2(g)} \rightleftharpoons NOBr_{2(g)}$
$NOBr_{2(g)} + NO_{(g)} \longrightarrow 2NOBr_{(g)}$
If the second step is the rate-determining step,the order of the reaction with respect to $NO_{(g)}$ is:
$NO_{(g)} + Br_{2(g)} \rightleftharpoons NOBr_{2(g)}$
$NOBr_{2(g)} + NO_{(g)} \longrightarrow 2NOBr_{(g)}$
If the second step is the rate-determining step,the order of the reaction with respect to $NO_{(g)}$ is:
DifficultAIEEE 2006
View SolutionWhich of the following statements is $NOT$ true about the rate constant $k$?
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