Medium
For the reaction $A + B \rightarrow \text{Product}$,if the concentration of $A$ is doubled,the reaction rate doubles. When the concentration of $B$ is doubled,the reaction rate remains unchanged. What is the overall order of the reaction?
- A$1$
- B$0$
- C$2$
- D$3$
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Similar Questions
Consider the following gas-phase reaction.
$2HI_{(g)} \longrightarrow H_{2(g)} + I_{2(g)}$
and the following experimental data obtained at $555 \ K$. What is the order of the reaction with respect to $HI_{(g)}$?
$[HI] \ (M)$ Rate $(M \ s^{-1})$ $0.0500$ $8.80 \times 10^{-10}$ $0.1000$ $3.52 \times 10^{-9}$ $0.1500$ $7.92 \times 10^{-9}$
$2HI_{(g)} \longrightarrow H_{2(g)} + I_{2(g)}$
and the following experimental data obtained at $555 \ K$. What is the order of the reaction with respect to $HI_{(g)}$?
| $[HI] \ (M)$ | Rate $(M \ s^{-1})$ |
| $0.0500$ | $8.80 \times 10^{-10}$ |
| $0.1000$ | $3.52 \times 10^{-9}$ |
| $0.1500$ | $7.92 \times 10^{-9}$ |
Medium
View SolutionWhat is the order of the following reaction: $2H_2O_2(l) \rightarrow 2H_2O(l) + O_2(g)$, given that the rate law is $\text{rate} = k[H_2O_2]^1$?
The mechanism of the reaction $A + 2B \to D$ is given by:
$2B \xrightarrow{k} B_2$ [Slow]
$B_2 + A \to D$ [Fast]
The rate law expression,order with respect to $A$,order with respect to $B$,and overall order are respectively:
$2B \xrightarrow{k} B_2$ [Slow]
$B_2 + A \to D$ [Fast]
The rate law expression,order with respect to $A$,order with respect to $B$,and overall order are respectively:
Medium
View SolutionWhich of the following is an elementary reaction?
For the reaction $A + 2B \longrightarrow C$, the reaction rate is doubled if the concentration of $A$ is doubled. The rate is increased by four times when concentrations of both $A$ and $B$ are increased by four times. The order of the reaction is
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