(C) The rate of the reaction is determined by the slow step:$Rate = k[NOBr_2][NO]$Since $NOBr_2$ is an intermediate,we express its concentration using

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The rate of the reaction is determined by the slow step:$Rate = k[NOBr_2][NO]$Since $NOBr_2$ is an intermediate,we express its concentration using the equilibrium constant $K_{eq}$ from the first step:$K_{eq} = \frac{[NOBr_2]}{[NO][Br_2]}$$[NOBr_2] = K_{eq}[NO][Br_2]$Substituting this into the rate equation:$Rate = k \cdot K_{eq}[NO][Br_2] \cdot [NO]$$Rate = k' [NO]^2 [Br_2]^1$The order of reaction with respect to $NO_{(g)}$ is the exponent of $[NO]$,which is $2$.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Medium

The mechanism of the reaction $2NO_{(g)} + Br_{2(g)} \rightarrow 2NOBr_{(g)}$ is given by:
$1) NO_{(g)} + Br_{2(g)} \rightleftharpoons NOBr_{2(g)}$ (fast)
$2) NOBr_{2(g)} + NO_{(g)} \rightarrow 2NOBr_{(g)}$ (slow)
If the second step is the rate-determining step,what is the order of the reaction with respect to $NO_{(g)}$?

A
$0$
B
$1$
C
$2$
D
$3$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

Rate law , Rate constant , Order of Reaction and Molecularity

What is a pseudo first order reaction? Give an example of a pseudo first order reaction.

Medium

View Solution

For a certain reaction $A_{(g)} \to B_{(g)}$,the half-life for different initial pressures of $A$ is given below:
$P_{A_0} \text{ (atm)}$ $0.1$ $0.025$
$t_{1/2} \text{ (sec)}$ $100$ $50$

The correct statement about the order of reaction is:

Medium

View Solution

For a given reaction $t_{1/2} = \frac{1}{k \cdot a}$,the order of reaction will be:

Easy

View Solution

For the reaction $A + 2B \longrightarrow C$, the reaction rate is doubled if the concentration of $A$ is doubled. The rate is increased by four times when concentrations of both $A$ and $B$ are increased by four times. The order of the reaction is

EasyWBJEE 2015

View Solution

In the reaction sequence $A$ $\xrightarrow{K_1} B$ $\xrightarrow{K_2} C$ $\xrightarrow{K_3} D$,where $K_3 > K_2 > K_1$,which step determines the rate of the reaction?

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$P_{A_0} \text{ (atm)}$	$0.1$	$0.025$
$t_{1/2} \text{ (sec)}$	$100$	$50$

Similar Questions

What is a pseudo first order reaction? Give an example of a pseudo first order reaction.

For a certain reaction $A_{(g)} \to B_{(g)}$,the half-life for different initial pressures of $A$ is given below:$P_{A_0} \text{ (atm)}$$0.1$$0.025$$t_{1/2} \text{ (sec)}$$100$$50$The correct statement about the order of reaction is:

For a given reaction $t_{1/2} = \frac{1}{k \cdot a}$,the order of reaction will be:

For the reaction $A + 2B \longrightarrow C$, the reaction rate is doubled if the concentration of $A$ is doubled. The rate is increased by four times when concentrations of both $A$ and $B$ are increased by four times. The order of the reaction is

In the reaction sequence $A$ $\xrightarrow{K_1} B$ $\xrightarrow{K_2} C$ $\xrightarrow{K_3} D$,where $K_3 > K_2 > K_1$,which step determines the rate of the reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

For a certain reaction $A_{(g)} \to B_{(g)}$,the half-life for different initial pressures of $A$ is given below:
$P_{A_0} \text{ (atm)}$ $0.1$ $0.025$
$t_{1/2} \text{ (sec)}$ $100$ $50$

The correct statement about the order of reaction is: