The $K_{sp}$ value of $AgCl$ at $25^{\circ}C$ is $1.8 \times 10^{-10}$. If $10^{-5} \ mol$ of $Ag^{+}$ is added to the solution,the new $K_{sp}$ value will be:
- A$1.8 \times 10^{-15}$
- B$1.8 \times 10^{-10}$
- C$1.8 \times 10^{-5}$
- D$1.8 \times 10^{-20}$
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