Easy
$3.1 \ mol$ of $FeCl_3$ and $3.2 \ mol$ of $NH_4SCN$ are added to $1 \ L$ of water. At equilibrium,$3.0 \ mol$ of $FeSCN^{2+}$ is formed. The equilibrium constant $K_c$ for the reaction is:
$Fe^{3+} + SCN^{-} \rightleftharpoons FeSCN^{2+}$
$Fe^{3+} + SCN^{-} \rightleftharpoons FeSCN^{2+}$
- A$6.66 \times 10^{-3}$
- B$0.3$
- C$3.3$
- D$150$
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