Medium
In a closed vessel,the dissociation of phosphorus pentachloride occurs as: $PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$. If the total pressure at equilibrium is $P$ and the degree of dissociation of $PCl_5$ is $x$,then the partial pressure of $PCl_3$ will be:
- A$\left( \frac{2x}{1-x} \right) P$
- B$\left( \frac{x}{x-1} \right) P$
- C$\left( \frac{x}{1+x} \right) P$
- D$\left( \frac{x}{x+1} \right) P$
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