Calculate the pH of a 1.0 , M ammonium format | vedclass

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Question

(A) Ammonium formate $(NH_4HCOO)$ is a salt of a weak acid $(HCOOH)$ and a weak base $(NH_4OH)$.The $pH$ of a salt of a weak acid and a weak base is g

Vedclass · Accepted Answer

$6.5$

Vedclass · Answer

(A) Ammonium formate $(NH_4HCOO)$ is a salt of a weak acid $(HCOOH)$ and a weak base $(NH_4OH)$.The $pH$ of a salt of a weak acid and a weak base is given by the formula:$pH = 7 + \frac{1}{2} pK_a - \frac{1}{2} pK_b$Given:$K_a = 1 	imes 10^{-4} \implies pK_a = -\log(1 	imes 10^{-4}) = 4$$K_b = 1 	imes 10^{-5} \implies pK_b = -\log(1 	imes 10^{-5}) = 5$Substituting the values into the formula:$pH = 7 + \frac{1}{2}(4) - \frac{1}{2}(5)$$pH = 7 + 2 - 2.5$$pH = 6.5$

Calculate the $pH$ of a $1.0 \, M$ ammonium formate solution,given that $K_a = 1 \times 10^{-4}$ and $K_b = 1 \times 10^{-5}$.

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