Given the following equilibria: K_1 : N_2 + 3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given reactions are: $(1) N_2 + 3H_2 \rightleftharpoons 2NH_3$ with constant $K_1$ $(2) N_2 + O_2 \rightleftharpoons 2NO$ with constant $K_2$

Vedclass · Accepted Answer

$\frac{K_2 K_3^3}{K_1}$

Vedclass · Answer

(C) The given reactions are: $(1) N_2 + 3H_2 ightleftharpoons 2NH_3$ with constant $K_1$ $(2) N_2 + O_2 ightleftharpoons 2NO$ with constant $K_2$ $(3) H_2 + 1/2 O_2 ightleftharpoons H_2O$ with constant $K_3$ We want to obtain the reaction: $2NH_3 + 5/2 O_2 ightleftharpoons 2NO + 3H_2O$ To get this,we reverse reaction $(1)$,add reaction $(2)$,and add $3$ times reaction $(3)$: Reverse $(1): 2NH_3 ightleftharpoons N_2 + 3H_2$ (Constant $= 1/K_1$) $(2): N_2 + O_2 ightleftharpoons 2NO$ (Constant $= K_2$) $3 	imes (3): 3H_2 + 3/2 O_2 ightleftharpoons 3H_2O$ (Constant $= K_3^3$) Adding these: $(2NH_3 + N_2 + 3H_2 + O_2 + 3/2 O_2) ightleftharpoons (N_2 + 3H_2 + 2NO + 3H_2O)$ Simplifying: $2NH_3 + 5/2 O_2 ightleftharpoons 2NO + 3H_2O$ The equilibrium constant $K$ is: $K = (1/K_1) 	imes K_2 	imes K_3^3 = \frac{K_2 K_3^3}{K_1}$.

Given the following equilibria:
$K_1 : N_2 + 3H_2 \rightleftharpoons 2NH_3$
$K_2 : N_2 + O_2 \rightleftharpoons 2NO$
$K_3 : H_2 + 1/2 O_2 \rightleftharpoons H_2O$
The equilibrium constant for the reaction $2NH_3 + 5/2 O_2 \rightleftharpoons 2NO + 3H_2O$ in terms of $K_1, K_2$,and $K_3$ is:

Similar Questions

The unit of equilibrium constant $K$ for the reaction $A + B \rightleftharpoons C$ would be

For ammonia formation from constituent elements,the expression for $K_{C}$ is

$2 NOCl_{(g)} \rightleftharpoons 2 NO_{(g)} + Cl_{2(g)}$
In an experiment,$2.0 \ mol$ of $NOCl$ was placed in a $1 \ L$ flask and the concentration of $NO$ after equilibrium was established,was found to be $0.4 \ mol/L$. The equilibrium constant at $30^{\circ} C$ is $....... \times 10^{-4}$.

$4.5$ moles each of hydrogen and iodine are heated in a sealed $10 \ L$ vessel. At equilibrium,$3$ moles of $HI$ are found. The equilibrium constant for ${H_2}_{(g)} + {I_2}_{(g)} \rightleftharpoons 2HI_{(g)}$ is

The dissociation of $SO_{3(g)}$ into $SO_{2(g)}$ and $O_{2(g)}$ is carried out in a closed container at a constant temperature $T$. The equilibrium constant for the reaction is $K_P = x \ atm$. The partial pressure variation for the three gases is as shown in the graph. The value of $x$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Given the following equilibria: $K_1 : N_2 + 3H_2 \rightleftharpoons 2NH_3$ $K_2 : N_2 + O_2 \rightleftharpoons 2NO$ $K_3 : H_2 + 1/2 O_2 \rightleftharpoons H_2O$ The equilibrium constant for the reaction $2NH_3 + 5/2 O_2 \rightleftharpoons 2NO + 3H_2O$ in terms of $K_1, K_2$,and $K_3$ is: