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(A) For the salt of a weak acid and a strong base,the hydrolysis constant is given by $K_h = \frac{K_w}{K_a}$.Taking the negative logarithm on both si

Vedclass · Accepted Answer

$pK_a + pK_h = pK_w$

Vedclass · Answer

(A) For the salt of a weak acid and a strong base,the hydrolysis constant is given by $K_h = \frac{K_w}{K_a}$.Taking the negative logarithm on both sides:$-\log K_h = -\log \left( \frac{K_w}{K_a} \right)$$-\log K_h = -(\log K_w - \log K_a)$$-\log K_h = -\log K_w + \log K_a$Rearranging the terms:$\log K_a - \log K_h = \log K_w$ is incorrect,rather:$pK_h = pK_w - pK_a$Therefore,$pK_a + pK_h = pK_w$.

For a weak acid with dissociation constant $K_a$ and its conjugate salt with hydrolysis constant $K_h$,which of the following represents their relationship?

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