In which of the following acid-base titration | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The $pH$ at the equivalence point of an acid-base titration depends on the nature of the salt formed.$1$. For a strong acid and strong base,the sa

Vedclass · Accepted Answer

Acetic acid vs. Sodium hydroxide

Vedclass · Answer

(B) The $pH$ at the equivalence point of an acid-base titration depends on the nature of the salt formed.$1$. For a strong acid and strong base,the salt formed is neutral $(pH \approx 7)$.$2$. For a strong acid and weak base,the salt undergoes cationic hydrolysis,resulting in an acidic solution $(pH $3$. For a weak acid and strong base,the salt undergoes anionic hydrolysis,resulting in a basic solution $(pH > 7)$.In the titration of acetic acid ($CH_3COOH$,a weak acid) against sodium hydroxide ($NaOH$,a strong base),the salt formed is sodium acetate $(CH_3COONa)$.$CH_3COO^- + H_2O \rightleftharpoons CH_3COOH + OH^-$The production of $OH^-$ ions makes the solution basic,hence the $pH$ at the equivalence point is greater than $8$.

In which of the following acid-base titrations is the $pH$ at the equivalence point greater than $8$?

Similar Questions

What is the degree of dissociation of $CH_3COOH$ if $\wedge^{\circ}(CH_3COO^{-}) = 50 \ S \ cm^2 \ mol^{-1}$,$\wedge^{\circ}(H^{+}) = 350 \ S \ cm^2 \ mol^{-1}$ and the molar conductivity of $5 \times 10^{-2} \ M \ CH_3COOH$ is $20 \ S \ cm^2 \ mol^{-1}$?

Formic acid $(HCOOH)$ is a weak acid and hydrochloric acid $(HCl)$ is a strong acid. It follows that the:

Which one of the following statements is not true?

Calculate the molar solubility of $AgCl$ at $25\,^oC$ in $3.0\ M\ NH_3$ ($K_{sp}$ of $AgCl = 2.0 \times 10^{-10}$,$K_f$ of $[Ag(NH_3)_2]^+ = 1.25 \times 10^7$) (in $M$)

The dissociation constant of acetic acid is $1.6 \times 10^{-5}$ and $\Lambda _{CH_3COOH}^o = 370.6 \times 10^{-4} \, S \, m^2 \, mol^{-1}$. The specific conductance of $0.01 \, M$ acetic acid solution will be approximately:

Vedclass Test Series

Exam Paper Generator

Online Exam Module