For the chemical reaction 3X_{(g)} + Y_{(g)} | vedclass

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(A) The given reaction is $3X_{(g)} + Y_{(g)} \rightleftharpoons X_3Y_{(g)}$.According to Le Chatelier's principle,the equilibrium position is affecte

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Temperature and pressure

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(A) The given reaction is $3X_{(g)} + Y_{(g)} \rightleftharpoons X_3Y_{(g)}$.According to Le Chatelier's principle,the equilibrium position is affected by changes in concentration,pressure,and temperature.$1$. Pressure: Since the number of moles of gaseous reactants $(3+1=4)$ is different from the number of moles of gaseous products $(1)$,a change in pressure will shift the equilibrium.$2$. Temperature: The formation of $X_3Y$ from $X$ and $Y$ involves a change in enthalpy,so temperature will affect the equilibrium constant and the position of equilibrium.$3$. Catalyst: $A$ catalyst only increases the rate of both forward and backward reactions equally and does not change the equilibrium position or the amount of products at equilibrium.Therefore,the amount of $X_3Y_{(g)}$ is affected by both temperature and pressure.

For the chemical reaction $3X_{(g)} + Y_{(g)} \rightleftharpoons X_3Y_{(g)}$,the amount of $X_3Y_{(g)}$ at equilibrium is affected by:

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