When hydrogen chloride is dissolved in acetic acid,the following equilibrium is established: $HCl + CH_3COOH \rightleftharpoons Cl^- + CH_3COOH_2^+$. Identify the conjugate acid-base pairs.
- A$(HCl, CH_3COOH)$ and $(CH_3COOH_2^+, Cl^-)$
- B$(HCl, CH_3COOH_2^+)$ and $(CH_3COOH, Cl^-)$
- C$(CH_3COOH_2^+, HCl)$ and $(Cl^-, CH_3COOH)$
- D$(HCl, Cl^-)$ and $(CH_3COOH_2^+, CH_3COOH)$
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View SolutionMatch the given ionisation constant values with the corresponding acids.
$A$. $HI$ $(i)$ $3.2 \times 10^9$ $B$. $HF$ $(ii)$ $3.5 \times 10^{-4}$ $C$. $HCl$ $(iii)$ $1.3 \times 10^6$ $D$. $HBr$ $(iv)$ $1.0 \times 10^9$
The correct match is:
| $A$. $HI$ | $(i)$ $3.2 \times 10^9$ |
| $B$. $HF$ | $(ii)$ $3.5 \times 10^{-4}$ |
| $C$. $HCl$ | $(iii)$ $1.3 \times 10^6$ |
| $D$. $HBr$ | $(iv)$ $1.0 \times 10^9$ |
The correct match is:
Values of dissociation constant,$K_a$ are given as follows:
Acid $K_a$ $HCN$ $6.2 \times 10^{-10}$ $HF$ $7.2 \times 10^{-4}$ $HNO_2$ $4.0 \times 10^{-4}$
Correct order of increasing base strength of the bases $CN^{-}$,$F^{-}$ and $NO_2^-$ will be:
| Acid | $K_a$ |
| $HCN$ | $6.2 \times 10^{-10}$ |
| $HF$ | $7.2 \times 10^{-4}$ |
| $HNO_2$ | $4.0 \times 10^{-4}$ |
Correct order of increasing base strength of the bases $CN^{-}$,$F^{-}$ and $NO_2^-$ will be:
DifficultJEE MAIN 2013
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