The hydrolysis constants of salts M_1X and M_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The basic strength is directly proportional to the dissociation constant of the base $(K_b)$.The relationship between hydrolysis constant $(K_h)$,

Vedclass · Accepted Answer

$M_3OH > M_1OH > M_2OH$

Vedclass · Answer

(A) The basic strength is directly proportional to the dissociation constant of the base $(K_b)$.The relationship between hydrolysis constant $(K_h)$,ionic product of water $(K_w)$,and base dissociation constant $(K_b)$ is given by: $K_h = \frac{K_w}{K_b}$,which implies $K_b = \frac{K_w}{K_h}$.Given $K_w = 10^{-14}$:$1$. For $M_1OH$ (from $M_1X$): $K_b(M_1OH) = \frac{10^{-14}}{10^{-7}} = 10^{-7}$.$2$. For $M_2OH$ (from $M_2X$): $K_b(M_2OH) = \frac{10^{-14}}{10^{-4}} = 10^{-10}$.$3$. For $M_3OH$: $K_b(M_3OH) = 10^{-4}$.Comparing the $K_b$ values: $10^{-4} > 10^{-7} > 10^{-10}$.Therefore,the decreasing order of basic strength is $M_3OH > M_1OH > M_2OH$.

The hydrolysis constants of salts $M_1X$ and $M_2X$ formed from a strong acid and weak bases are $10^{-7}$ and $10^{-4}$ respectively. For base $M_3OH$,$K_b = 10^{-4}$. The decreasing order of basic strength is:

Similar Questions

$2.5 \ mL$ of $\frac{2}{5} \ M$ weak monoacidic base ($K_{b} = 1 \times 10^{-12}$ at $25^{\circ} C$) is titrated with $\frac{2}{15} \ M \ HCl$ in water at $25^{\circ} C$. The concentration of $H^{+}$ at equivalence point is ($K_W = 1 \times 10^{-14}$ at $25^{\circ} C$).

The first and second dissociation constants of a diprotic acid ${H_2}A$ are $1.0 \times 10^{-5}$ and $5.0 \times 10^{-10}$ respectively. The overall dissociation constant of the acid ${H_2}A$ is .......

$20 \ mL$ of $0.5 \ N \ HCl$ and $35 \ mL$ of $0.1 \ N \ NaOH$ are mixed. The resulting solution will

At $25^{\circ} C$, the molar conductance of $0.007 \ M$ hydrofluoric acid is $150 \ \text{mho} \ cm^{2} \ mol^{-1}$ and its $\Lambda_{m}^{\circ} = 500 \ \text{mho} \ cm^{2} \ mol^{-1}$. The value of the dissociation constant of the acid at the given concentration at $25^{\circ} C$ is

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$2NaOH + Zn(OH)_2 \rightarrow Na_2ZnO_2 + 2H_2O$

Vedclass Test Series

Exam Paper Generator

Online Exam Module