The equilibrium constants for three reactions | vedclass

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Question

(B) The given reactions are:$(I) \, CO_{(g)} + H_2O_{(g)} \rightleftharpoons CO_{2_{(g)}} + H_{2_{(g)}} ; \, k_1$$(II) \, CH_{4_{(g)}} + H_2O_{(g)} \r

Vedclass · Accepted Answer

$k_3 = k_1 k_2$

Vedclass · Answer

(B) The given reactions are:$(I) \, CO_{(g)} + H_2O_{(g)} ightleftharpoons CO_{2_{(g)}} + H_{2_{(g)}} ; \, k_1$$(II) \, CH_{4_{(g)}} + H_2O_{(g)} ightleftharpoons CO_{(g)} + 3H_{2_{(g)}} ; \, k_2$$(III) \, CH_{4_{(g)}} + 2H_2O_{(g)} ightleftharpoons CO_{2_{(g)}} + 4H_{2_{(g)}} ; \, k_3$Observe that adding reaction $(I)$ and reaction $(II)$ gives reaction $(III)$:$(CO_{(g)} + H_2O_{(g)}) + (CH_{4_{(g)}} + H_2O_{(g)}) ightleftharpoons (CO_{2_{(g)}} + H_{2_{(g)}}) + (CO_{(g)} + 3H_{2_{(g)}})$Canceling common terms $(CO_{(g)})$ on both sides:$CH_{4_{(g)}} + 2H_2O_{(g)} ightleftharpoons CO_{2_{(g)}} + 4H_{2_{(g)}}$Since reaction $(III) = (I) + (II)$,the equilibrium constant $k_3$ is the product of $k_1$ and $k_2$:$k_3 = k_1 	imes k_2$

Similar Questions

For the reaction $2H_2S_{(g)} \rightleftharpoons 2H_{2(g)} + S_{2(g)}$,the equilibrium mixture is given. If $1 \ mol$ of $H_2S$,$0.2 \ mol$ of $H_2$,and $0.8 \ mol$ of $S_2$ are taken in a $2 \ L$ vessel,find the value of $K_c$.

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