For a 10 M CH_3COOH solution,if K_a = 10^{- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a weak acid,the dissociation constant is given by $K_a = C\alpha^2$,where $C$ is the concentration and $\alpha$ is the degree of dissociation.

Vedclass · Accepted Answer

$10^{-2}, 2$

Vedclass · Answer

(B) For a weak acid,the dissociation constant is given by $K_a = C\alpha^2$,where $C$ is the concentration and $\alpha$ is the degree of dissociation.Given $K_a = 10^{-5}$ and $C = 10 \ M$.$10^{-5} = 10 	imes \alpha^2$ $\Rightarrow \alpha^2 = 10^{-6}$ $\Rightarrow \alpha = 10^{-3}$.The concentration of hydrogen ions is $[H^+] = C\alpha = 10 	imes 10^{-3} = 10^{-2} \ M$.The $pH$ is calculated as $pH = -\log[H^+] = -\log(10^{-2}) = 2$.

For a $10 \ M \ CH_3COOH$ solution,if $K_a = 10^{-5}$,what will be the values of $[H^{+}]$ and $pH$ respectively?

Similar Questions

The degree of ionization of $0.4 \ M$ acetic acid will be $(K_{a} = 1.8 \times 10^{-5})$.

What is the $pH$ of a $2 \times 10^{-3} \ M$ solution of a monoacidic weak base if it ionizes to the extent of $5 \%$?

Find the $pOH$ value of $10^{-3} \ M \ NH_4OH$. Given $K_b = 10^{-5}$.

If the ionization constant of hypochlorous acid $(HOCl)$ is $2.5 \times 10^{-5}$,the $pH$ of $1.0 \ M$ of its solution is $(\log 5=0.7)$.

The $pH$ of a $0.1 \ M$ solution of the acid $HQ$ is $3$. The value of the ionization constant,$K_a$ of the acid is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module