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(B) Sodium acetate $(CH_3COONa)$ undergoes hydrolysis in water as follows:$CH_3COO^{-} + H_2O ⇌ CH_3COOH + OH^{-}$According to the stoichiometry of th

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$[OH^{-}]$

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(B) Sodium acetate $(CH_3COONa)$ undergoes hydrolysis in water as follows:$CH_3COO^{-} + H_2O ⇌ CH_3COOH + OH^{-}$According to the stoichiometry of the hydrolysis reaction,for every mole of $CH_3COOH$ produced,one mole of $OH^{-}$ is also produced.Therefore,in an aqueous solution of sodium acetate,the concentration of acetic acid formed is equal to the concentration of hydroxide ions produced:$[CH_3COOH] = [OH^{-}]$

In a solution of sodium acetate,the concentration of $CH_3COOH$ is equal to which of the following?

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