$A$ body moves a distance of $10 \ m$ along a straight line under the action of a force of $5 \ N$. If the work done in this process is $25 \ J$,what is the angle between the force and the displacement in degrees?

$A$ body of mass $10\, kg$ is dropped to the ground from a height of $10\, m$. The work done by the gravitational force is ............. $J$ $(g = 9.8\, m/s^2)$.

The work done in pulling up a block of wood weighing $2 \, kN$ for a length of $10 \, m$ on a smooth plane inclined at an angle of $15^\circ$ with the horizontal is ............. $kJ$.

$A$ body of mass $2 \ kg$ is moving along the $x$-direction such that its displacement as a function of time is given by $x(t) = \alpha t^2 + \beta t + \gamma \ m$, where $\alpha = 1 \ m/s^2$, $\beta = 1 \ m/s$, and $\gamma = 1 \ m$. The work done on the body during the time interval $t = 2 \ s$ to $t = 3 \ s$ is . . . . . . $J$.

When is the work done by a force positive and when is it negative?

$A$ particle moves from position $\vec{r_1} = 3\,\hat{i} + 2\,\hat{j} - 6\,\hat{k}$ to position $\vec{r_2} = 14\,\hat{i} + 13\,\hat{j} + 9\,\hat{k}$ under the influence of a force $\vec{F} = 4\,\hat{i} + \hat{j} + 3\,\hat{k}$. Find the work done in $J$.