Class 11PhysicsNewton's Laws of Motion and FrictionKinetic Friction and Motion on Rough Horizontal Surface
MediumCalculate the stopping distance of a vehicle of mass $M$ moving with velocity $v$ on a straight road. (Where $\mu$ is the coefficient of friction between the tires and the road.)
- A$S = \frac{v}{2\mu g}$
- B$S = \frac{v^2}{\mu g}$
- C$S = \frac{v}{\mu g}$
- D$S = \frac{v^2}{2\mu g}$
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Similar Questions
$A$ block of mass $5\, kg$ is on a rough horizontal surface and is at rest. Now a force of $24\, N$ is imparted to it with negligible impulse. If the coefficient of kinetic friction is $0.4$ and $g = 9.8\, m/s^2$,then the acceleration of the block is ........ $m/s^2$.
Medium
View SolutionOn a rough horizontal surface,a body of mass $2 \, kg$ is given a velocity of $10 \, m/s$. If the coefficient of friction is $0.2$ and $g = 10 \, m/s^2$,the body will stop after covering a distance of ........ $m$.
Medium
View Solution$A$ block of mass $4\,kg$ is placed on a rough horizontal plane. $A$ time-dependent force $F = kt^2$ acts on the block,where $k = 2\,N/s^2$. The coefficient of friction is $\mu = 0.8$. The force of friction between the block and the plane at $t = 2\,s$ is ....... $N$.
Medium
View SolutionWhat is the angle between the instantaneous velocity and the friction force of an object moving on a rough surface (in $^{\circ}$)?
Easy
View Solution$A$ block of mass $m$ placed on a rough horizontal plane is pulled by a constant power $P$. The coefficient of friction between the block and the surface is $\mu$. The maximum velocity of the block will be
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