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(B) The power $P$ required to move a body up an inclined plane at a constant velocity $v$ is given by $P = F \cdot v$.Here,the force $F$ required to o

Vedclass · Accepted Answer

$20$

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(B) The power $P$ required to move a body up an inclined plane at a constant velocity $v$ is given by $P = F \cdot v$.Here,the force $F$ required to overcome gravity is $F = mg \sin 	heta$.Given: mass $m = 10000 \ kg$,length $l = 50 \ m$,height $h = 1 \ m$,speed $v = 36 \ km/h = 36 	imes \frac{5}{18} = 10 \ m/s$.The sine of the angle of inclination is $\sin 	heta = \frac{h}{l} = \frac{1}{50}$.Taking acceleration due to gravity $g = 10 \ m/s^2$,the power is:$P = (mg \sin 	heta) 	imes v$$P = 10000 	imes 10 	imes \frac{1}{50} 	imes 10$$P = 10000 	imes 10 	imes 0.02 	imes 10 = 20000 \ W$$P = 20 \ kW$.

$A$ truck of mass $10000 \ kg$ is moving up an inclined plane with a length of $50 \ m$ and a height of $1 \ m$ at a speed of $36 \ km/h$. What is the power of the engine in $kW$?

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