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(C) The coefficient of performance $(COP)$ of an ideal refrigerator is given by the formula: $\alpha = \frac{T_2}{T_1 - T_2}$,where $T_2$ is the tempe

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$39 \, ^\circ C$

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(C) The coefficient of performance $(COP)$ of an ideal refrigerator is given by the formula: $\alpha = \frac{T_2}{T_1 - T_2}$,where $T_2$ is the temperature of the cold reservoir and $T_1$ is the temperature of the hot reservoir (surroundings).Given: $T_2 = -13 \, ^\circ C = 273 - 13 = 260 \, K$ and $\alpha = 5$.Substituting the values into the formula:$5 = \frac{260}{T_1 - 260}$$5(T_1 - 260) = 260$$T_1 - 260 = \frac{260}{5} = 52$$T_1 = 260 + 52 = 312 \, K$.Converting back to Celsius: $T_1 = 312 - 273 = 39 \, ^\circ C$.

The temperature of the freezer compartment of an ideal refrigerator is $-13 \, ^\circ C$. If the coefficient of performance of the refrigerator is $5$,then the temperature of the surroundings (to which heat is rejected) is:

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