A total radiation of 400 J is incident on a | vedclass

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(A) The total incident radiation $Q = 400 \ J$. The reflected radiation $Q_r = 20\% 	ext{ of } 400 \ J = 0.20 	imes 400 = 80 \ J$. The absorbed radi

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(A) The total incident radiation $Q = 400 \ J$. The reflected radiation $Q_r = 20\% 	ext{ of } 400 \ J = 0.20 	imes 400 = 80 \ J$. The absorbed radiation $Q_a = 120 \ J$. According to the law of conservation of energy,$Q = Q_r + Q_a + Q_t$,where $Q_t$ is the transmitted radiation. Substituting the values: $400 = 80 + 120 + Q_t$. $400 = 200 + Q_t \implies Q_t = 200 \ J$. The percentage of transmittive power is given by $\frac{Q_t}{Q} 	imes 100 = \frac{200}{400} 	imes 100 = 50\%$.

$A$ total radiation of $400 \ J$ is incident on a body. If $20\%$ of the radiation is reflected and $120 \ J$ is absorbed,find the percentage of the transmittive power.

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