Find the rate of energy radiated per minute b | vedclass

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(D) According to the Stefan-Boltzmann law,the power radiated by a body is given by $P = \sigma e A T^{4}$.Given:$\sigma = 5.7 	imes 10^{-8} \ W \ m^{

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$2325$

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(D) According to the Stefan-Boltzmann law,the power radiated by a body is given by $P = \sigma e A T^{4}$.Given:$\sigma = 5.7 	imes 10^{-8} \ W \ m^{-2} \ K^{-4}$$e = 0.85$$A = 5 	imes 10^{-5} \ m^{2}$$T = 2000 \ K$First,calculate the power $P$ (energy per second):$P = (5.7 	imes 10^{-8}) 	imes 0.85 	imes (5 	imes 10^{-5}) 	imes (2000)^{4}$$P = 5.7 	imes 0.85 	imes 5 	imes 10^{-13} 	imes 16 	imes 10^{12}$$P = 5.7 	imes 0.85 	imes 5 	imes 16 	imes 10^{-1}$$P = 38.76 \ W$ (Joules per second).To find the energy radiated per minute,multiply by $60 \ s$:$E = P 	imes 60 = 38.76 	imes 60 = 2325.6 \ J$.Rounding to the nearest given option,the answer is $2325 \ J$.

Find the rate of energy radiated per minute by an incandescent lamp at $2000 \ K$. The surface area is $5 \times 10^{-5} \ m^{2}$,the emissivity is $0.85$,and $\sigma = 5.7 \times 10^{-8} \ W \ m^{-2} \ K^{-4}$. (in $J$)

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