The phenomenon of superconductivity is observ | vedclass

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(A) The relationship between the Kelvin scale $(T_K)$ and the Celsius scale $(T_C)$ is given by $T_C = T_K - 273.15$. Taking $T_K = 95 \ K$,we get $T_

Vedclass · Accepted Answer

$-288$

Vedclass · Answer

(A) The relationship between the Kelvin scale $(T_K)$ and the Celsius scale $(T_C)$ is given by $T_C = T_K - 273.15$. Taking $T_K = 95 \ K$,we get $T_C = 95 - 273 = -178 \ ^\circ C$.The relationship between the Fahrenheit scale $(T_F)$ and the Celsius scale $(T_C)$ is given by $T_F = \frac{9}{5} T_C + 32$.Substituting the value of $T_C$:$T_F = \frac{9}{5}(-178) + 32$$T_F = -320.4 + 32$$T_F = -288.4 \ ^\circ F$.Rounding to the nearest integer,the value is $-288 \ ^\circ F$.

The phenomenon of superconductivity is observed at a temperature of $95 \ K$. The corresponding temperature on the Fahrenheit scale is ...... $^\circ F$.

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