The maximum electron density of the ionospher | vedclass

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Question

(B) The critical frequency $f_c$ of the ionosphere is given by the formula $f_c = 9 \sqrt{N_{\max}}$,where $N_{\max}$ is the maximum electron density.

Vedclass · Accepted Answer

$1.414$

Vedclass · Answer

(B) The critical frequency $f_c$ of the ionosphere is given by the formula $f_c = 9 \sqrt{N_{\max}}$,where $N_{\max}$ is the maximum electron density.Let $N_1 = 10^{10} \ m^{-3}$ be the density in the morning and $N_2 = 2 	imes 10^{10} \ m^{-3}$ be the density at noon.The critical frequency in the morning is $f_{c1} = 9 \sqrt{N_1}$.The critical frequency at noon is $f_{c2} = 9 \sqrt{N_2}$.The ratio of the critical frequency at noon to the critical frequency in the morning is $\frac{f_{c2}}{f_{c1}} = \frac{9 \sqrt{N_2}}{9 \sqrt{N_1}} = \sqrt{\frac{N_2}{N_1}}$.Substituting the values: $\frac{f_{c2}}{f_{c1}} = \sqrt{\frac{2 	imes 10^{10}}{10^{10}}} = \sqrt{2} \approx 1.414$.

The maximum electron density of the ionosphere layer in the morning is $10^{10} \ m^{-3}$. At noon,the maximum electron density increases to $2 \times 10^{10} \ m^{-3}$. What is the ratio of the critical frequency at noon to the critical frequency in the morning?

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