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(A) Given: Carrier frequency $f_c = 1 MHz = 1000 kHz$,modulating frequency $f_m = 10 kHz = 0.01 MHz$.Carrier amplitude $A_c = 10 V$,modulating amplitu

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$0.05$ and $1 \pm 0.010 MHz$

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(A) Given: Carrier frequency $f_c = 1 MHz = 1000 kHz$,modulating frequency $f_m = 10 kHz = 0.01 MHz$.Carrier amplitude $A_c = 10 V$,modulating amplitude $A_m = 0.5 V$.Modulation index $\mu = \frac{A_m}{A_c} = \frac{0.5}{10} = 0.05$.The frequencies of the sidebands are given by $f_c \pm f_m$.$USB = f_c + f_m = 1 MHz + 0.01 MHz = 1.01 MHz$.$LSB = f_c - f_m = 1 MHz - 0.01 MHz = 0.99 MHz$.Thus,the sideband frequencies are $1 \pm 0.01 MHz$.

The frequency of a carrier wave is $1 MHz$. It is modulated by a wave of frequency $10 kHz$. If their amplitudes are $10 V$ and $0.5 V$ respectively,what are the modulation index and the frequencies of the $USB$ and $LSB$?

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