What is the amplitude of the LSB (Lower Side | vedclass

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(A) From the given figure,the maximum and minimum amplitudes of the $AM$ wave are:$E_{	ext{max}} = 100 \ V$$E_{	ext{min}} = 60 \ V$The carrier wave

Vedclass · Accepted Answer

$10$

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(A) From the given figure,the maximum and minimum amplitudes of the $AM$ wave are:$E_{	ext{max}} = 100 \ V$$E_{	ext{min}} = 60 \ V$The carrier wave amplitude $E_c$ is given by:$E_c = \frac{E_{	ext{max}} + E_{	ext{min}}}{2} = \frac{100 + 60}{2} = 80 \ V$The modulation index $m_a$ is given by:$m_a = \frac{E_{	ext{max}} - E_{	ext{min}}}{E_{	ext{max}} + E_{	ext{min}}} = \frac{100 - 60}{100 + 60} = \frac{40}{160} = 0.25$The amplitude of the $LSB$ (or $USB$) is given by:$A_{LSB} = \frac{m_a}{2} E_c = \frac{0.25}{2} 	imes 80 = 0.125 	imes 80 = 10 \ V$

What is the amplitude of the $LSB$ (Lower Side Band) frequency in the $AM$ wave shown in the figure (in $V$)?

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