The freezing point depression of a $0.01 \ m$ aqueous solution of $[Pt(NH_3)_4Cl_4]$ is $0.0054^\circ C$. If $K_f$ for water is $1.80 \ K \ kg \ mol^{-1}$,what is the correct formula for the complex?

  • A
    $[Pt(NH_3)_4Cl_3]Cl$
  • B
    $[Pt(NH_3)_4Cl_2]Cl_2$
  • C
    $[Pt(NH_3)_4Cl]Cl_3$
  • D
    $[Pt(NH_3)_4Cl_4]$

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