(B) The molar mass of $N_2 = 28 \ g/mol$ and $O_2 = 32 \ g/mol$. Number of moles of $N_2 (n_{N_2}) = \frac{7}{28} = 0.25 \ mol$. Number of moles of $O

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(B) The molar mass of $N_2 = 28 \ g/mol$ and $O_2 = 32 \ g/mol$. Number of moles of $N_2 (n_{N_2}) = \frac{7}{28} = 0.25 \ mol$. Number of moles of $O_2 (n_{O_2}) = \frac{8}{32} = 0.25 \ mol$. Mole fraction of $O_2 (x_{O_2}) = \frac{n_{O_2}}{n_{N_2} + n_{O_2}} = \frac{0.25}{0.25 + 0.25} = \frac{0.25}{0.50} = 0.5$.

Class 11 Chemistry Some Basic Concepts of Chemistry The mole concept

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What is the mole fraction of oxygen in a mixture of $7 \ g$ of nitrogen and $8 \ g$ of oxygen?

A
$8/15$
B
$0.5$
C
$0.25$
D
$1.0$

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Class 11

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Some Basic Concepts of Chemistry

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The mole concept

If $19.7 \ kg$ of gold is confiscated from a thief,how many atoms of gold were confiscated from him? $(Au = 197 \ g/mol)$

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If the price of $1 \ kg$ of common salt is $7$ rupees and the price of $1 \ kg$ of sugar is $14$ rupees,then what is the cost of $1 \ mole$ of salt and sugar?

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What is the volume occupied by $16 \ g$ methane gas at $STP$ (in $cm^3$)?

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$10 \ g$ each of $CO_2$,$NH_3$,and $O_2$ were taken in three separate flasks. What is the correct decreasing order of the number of atoms?

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How many protons are present in $1.8 \ g$ of $NH_{4}^{+}$?

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What is the mole fraction of oxygen in a mixture of $7 \ g$ of nitrogen and $8 \ g$ of oxygen?

Similar Questions

If $19.7 \ kg$ of gold is confiscated from a thief,how many atoms of gold were confiscated from him? $(Au = 197 \ g/mol)$

If the price of $1 \ kg$ of common salt is $7$ rupees and the price of $1 \ kg$ of sugar is $14$ rupees,then what is the cost of $1 \ mole$ of salt and sugar?

What is the volume occupied by $16 \ g$ methane gas at $STP$ (in $cm^3$)?

$10 \ g$ each of $CO_2$,$NH_3$,and $O_2$ were taken in three separate flasks. What is the correct decreasing order of the number of atoms?

How many protons are present in $1.8 \ g$ of $NH_{4}^{+}$?

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