Which of the following has the highest boilin | vedclass

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(C) The elevation in boiling point is given by $\Delta T_b = i 	imes K_b 	imes m$. Since $K_b$ is constant,$\Delta T_b$ depends on the product of th

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$0.1 \, M \, Al_2(SO_4)_3$

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(C) The elevation in boiling point is given by $\Delta T_b = i 	imes K_b 	imes m$. Since $K_b$ is constant,$\Delta T_b$ depends on the product of the van't Hoff factor $(i)$ and the molarity $(M)$. For $0.1 \, N \, Na_2SO_4$,$M = 0.1 / 2 = 0.05 \, M$,so $i 	imes M = 3 	imes 0.05 = 0.15$. For $0.1 \, N \, MgSO_4$,$M = 0.1 / 2 = 0.05 \, M$,so $i 	imes M = 2 	imes 0.05 = 0.10$. For $0.1 \, M \, Al_2(SO_4)_3$,$i = 5$,so $i 	imes M = 5 	imes 0.1 = 0.50$. For $0.1 \, M \, BaSO_4$,$i = 2$ (assuming complete dissociation),so $i 	imes M = 2 	imes 0.1 = 0.20$. Since $Al_2(SO_4)_3$ has the highest value of $i 	imes M$,it has the highest boiling point.

Which of the following has the highest boiling point?

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