If 2 g of NaOH is dissolved in water to make | vedclass

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(B) The molar mass of $NaOH$ is $40 \ g/mol$. Since the valency factor ($n$-factor) of $NaOH$ is $1$,the equivalent mass is also $40 \ g/eq$. Number o

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$N/2$

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(B) The molar mass of $NaOH$ is $40 \ g/mol$. Since the valency factor ($n$-factor) of $NaOH$ is $1$,the equivalent mass is also $40 \ g/eq$. Number of gram equivalents of $NaOH = \frac{	ext{mass}}{	ext{equivalent mass}} = \frac{2 \ g}{40 \ g/eq} = \frac{1}{20} \ eq$. Volume of solution = $100 \ cm^3 = 0.1 \ L$. Normality $(N)$ = $\frac{	ext{Number of gram equivalents}}{	ext{Volume of solution in } L} = \frac{1/20 \ eq}{0.1 \ L} = \frac{1}{2} \ N$ or $N/2$.

If $2 \ g$ of $NaOH$ is dissolved in water to make a $100 \ cm^3$ solution,what is the normality of this solution?

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