The vapor pressures of two liquids $A$ and $B$ are $80 \ mm$ and $60 \ mm$ respectively. If $3 \ mol$ of $A$ and $2 \ mol$ of $B$ are mixed,the total vapor pressure of the resulting solution will be .......... $mm$.

  • A
    $140$
  • B
    $20$
  • C
    $68$
  • D
    $72$

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$160 \ g$ of non-volatile solute '$A$' is dissolved in $54 \ mL$ of water at $373 \ K$. What is the vapour pressure of the aqueous solution of '$A$' (in $Torr$)? (Given: molecular weight of '$A$' = $160 \ g \ mol^{-1}$)

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Reason $(R)$: Lowering of vapour pressure is directly proportional to the number of particles of non-volatile solute present in the solution.
The correct answer is

On adding a solute to a solvent having a vapour pressure of $0.80 \ atm$,the vapour pressure reduces to $0.60 \ atm$. The mole fraction of the solute is:

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