Which solution is required to completely neut | vedclass

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(C) For complete neutralization,the number of equivalents of acid must be equal to the number of equivalents of base. According to the law of equivale

Vedclass · Accepted Answer

$25 \ mL$ of $N/10$ $HCl$ solution

Vedclass · Answer

(C) For complete neutralization,the number of equivalents of acid must be equal to the number of equivalents of base. According to the law of equivalence: $N_1V_1 = N_2V_2$. Given: $N_1 = N/10 = 0.1 \ N$,$V_1 = 25 \ mL$. We need $N_2V_2 = 0.1 	imes 25 = 2.5 \ meq$. Checking option $C$: $N_2 = N/10 = 0.1 \ N$,$V_2 = 25 \ mL$. $N_2V_2 = 0.1 	imes 25 = 2.5 \ meq$. Since the equivalents of $HCl$ match the equivalents of $NaOH$,option $C$ is correct.

Which solution is required to completely neutralize $25 \ mL$ of $N/10$ $NaOH$ solution?

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