A solution containing 10 g of urea (molar ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For isotonic solutions,the osmotic pressure $(\pi)$ is equal,which means their molar concentrations $(C)$ are equal at the same temperature.$C_1 =

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(B) For isotonic solutions,the osmotic pressure $(\pi)$ is equal,which means their molar concentrations $(C)$ are equal at the same temperature.$C_1 = C_2$$\frac{n_1}{V_1} = \frac{n_2}{V_2}$Given for urea: Mass $= 10 \ g$,Molar mass $= 60 \ g \ mol^{-1}$,Volume $= 1 \ L$.$n_1 = \frac{10}{60} = \frac{1}{6} \ mol$.$C_1 = \frac{1/6}{1} = \frac{1}{6} \ mol \ L^{-1}$.Given for non-volatile solute: $5 \% \ w/v$ means $5 \ g$ in $100 \ mL$,which is $50 \ g$ in $1 \ L$.Let the molar mass be $M_2$.$n_2 = \frac{50}{M_2}$.$C_2 = \frac{50}{M_2} \ mol \ L^{-1}$.Equating $C_1 = C_2$:$\frac{1}{6} = \frac{50}{M_2}$$M_2 = 50 	imes 6 = 300 \ g \ mol^{-1}$.

$A$ solution containing $10 \ g$ of urea (molar mass $= 60 \ g \ mol^{-1}$) per liter is isotonic with a $5 \% \ w/v$ solution of a non-volatile solute. The molar mass of the non-volatile solute is ......... $g \ mol^{-1}$.

Similar Questions

Isotonic solutions have

The correct relationship between the osmotic pressure of $0.1 \ M \ NaCl$ and $0.1 \ M \ Na_2SO_4$ is ......

Which of the following pairs of solutions are expected to be isotonic,temperature being the same?

The ideal method to determine osmotic pressure is ...... .

Among the colligative properties,which one is the best method for the determination of the molar mass of proteins and polymers?

Vedclass Test Series

Exam Paper Generator

Online Exam Module